Base | Representation |
---|---|
bin | 1011000001000101001100… |
… | …0110100011000111110011 |
3 | 1120220000021212121112220212 |
4 | 2300101103012203013303 |
5 | 3041430314203002441 |
6 | 41432421141454335 |
7 | 2360102303104013 |
oct | 260212306430763 |
9 | 46800255545825 |
10 | 12113202000371 |
11 | 39501a881420a |
12 | 1437752a113ab |
13 | 69b3683a8964 |
14 | 2dc3d414bc43 |
15 | 16015b1adeeb |
hex | b04531a31f3 |
12113202000371 has 2 divisors, whose sum is σ = 12113202000372. Its totient is φ = 12113202000370.
The previous prime is 12113202000293. The next prime is 12113202000461. The reversal of 12113202000371 is 17300020231121.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12113202000371 is a prime.
It is not a weakly prime, because it can be changed into another prime (12113202000671) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6056601000185 + 6056601000186.
It is an arithmetic number, because the mean of its divisors is an integer number (6056601000186).
Almost surely, 212113202000371 is an apocalyptic number.
12113202000371 is a deficient number, since it is larger than the sum of its proper divisors (1).
12113202000371 is an equidigital number, since it uses as much as digits as its factorization.
12113202000371 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 504, while the sum is 23.
Adding to 12113202000371 its reverse (17300020231121), we get a palindrome (29413222231492).
The spelling of 12113202000371 in words is "twelve trillion, one hundred thirteen billion, two hundred two million, three hundred seventy-one", and thus it is an aban number.
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