Base | Representation |
---|---|
bin | 1011000001000101001110… |
… | …1101100000001110000101 |
3 | 1120220000022120211100210002 |
4 | 2300101103231200032011 |
5 | 3041430324311241401 |
6 | 41432422144411045 |
7 | 2360102455644560 |
oct | 260212355401605 |
9 | 46800276740702 |
10 | 12113212212101 |
11 | 3950203559460 |
12 | 1437756316a85 |
13 | 69b36a5429c0 |
14 | 2dc3d56494d7 |
15 | 16015c029a6b |
hex | b0453b60385 |
12113212212101 has 16 divisors (see below), whose sum is σ = 16263893321088. Its totient is φ = 8712799992000.
The previous prime is 12113212212097. The next prime is 12113212212139. The reversal of 12113212212101 is 10121221231121.
It is not a de Polignac number, because 12113212212101 - 22 = 12113212212097 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12113212212001) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6050554550 + ... + 6050556551.
It is an arithmetic number, because the mean of its divisors is an integer number (1016493332568).
Almost surely, 212113212212101 is an apocalyptic number.
12113212212101 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
It is an amenable number.
12113212212101 is a deficient number, since it is larger than the sum of its proper divisors (4150681108987).
12113212212101 is a wasteful number, since it uses less digits than its factorization.
12113212212101 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12101111132.
The product of its (nonzero) digits is 96, while the sum is 20.
Adding to 12113212212101 its reverse (10121221231121), we get a palindrome (22234433443222).
The spelling of 12113212212101 in words is "twelve trillion, one hundred thirteen billion, two hundred twelve million, two hundred twelve thousand, one hundred one".
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