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121133000000 = 2656294177
BaseRepresentation
bin111000011010000010…
…1101110010101000000
3102120122222002222022102
41300310011232111000
53441040022000000
6131351524325532
711515534340255
oct1606405562500
9376588088272
10121133000000
1147410469861
121b5872438a8
13b565b5067c
145c119d542c
15323e6a93d5
hex1c3416e540

121133000000 has 196 divisors, whose sum is σ = 310897973580. Its totient is φ = 46771200000.

The previous prime is 121132999951. The next prime is 121133000063. The reversal of 121133000000 is 331121.

It can be written as a sum of positive squares in 14 ways, for example, as 118038970624 + 3094029376 = 343568^2 + 55624^2 .

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 27 ways as a sum of consecutive naturals, for example, 28997912 + ... + 29002088.

Almost surely, 2121133000000 is an apocalyptic number.

121133000000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 121133000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (155448986790).

121133000000 is an abundant number, since it is smaller than the sum of its proper divisors (189764973580).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

121133000000 is an frugal number, since it uses more digits than its factorization.

121133000000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4248 (or 4213 counting only the distinct ones).

The product of its (nonzero) digits is 18, while the sum is 11.

Adding to 121133000000 its reverse (331121), we get a palindrome (121133331121).

The spelling of 121133000000 in words is "one hundred twenty-one billion, one hundred thirty-three million", and thus it is an aban number.