1211330223141 has 4 divisors (see below), whose sum is σ = 1615106964192. Its totient is φ = 807553482092.

The previous prime is 1211330223139. The next prime is 1211330223163. The reversal of 1211330223141 is 1413220331121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1211330223141 - 2¹ = 1211330223139 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1211330223121) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 201888370521 + ... + 201888370526.

It is an arithmetic number, because the mean of its divisors is an integer number (403776741048).

Almost surely, 2^{1211330223141} is an apocalyptic number.

It is an amenable number.

1211330223141 is a deficient number, since it is larger than the sum of its proper divisors (403776741051).

1211330223141 is an equidigital number, since it uses as much as digits as its factorization.

1211330223141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 403776741050.

The product of its (nonzero) digits is 864, while the sum is 24.

Adding to 1211330223141 its reverse (1413220331121), we get a palindrome (2624550554262).

The spelling of 1211330223141 in words is "one trillion, two hundred eleven billion, three hundred thirty million, two hundred twenty-three thousand, one hundred forty-one".