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12113313333000 = 23353111931623209
BaseRepresentation
bin1011000001000101100110…
…1111001111111100001000
31120220000120122002211120120
42300101121233033330020
53041431031203124000
641432440200023240
72360105124315645
oct260213157177410
946800518084516
1012113313333000
113950255646050
121437784161b20
1369b385489759
142dc404c4cdcc
15160165d516a0
hexb0459bcff08

12113313333000 has 512 divisors, whose sum is σ = 44799326208000. Its totient is φ = 2692258560000.

The previous prime is 12113313332957. The next prime is 12113313333029. The reversal of 12113313333000 is 33331331121.

12113313333000 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a Harshad number since it is a multiple of its sum of digits (24).

It is an unprimeable number.

It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 19125396 + ... + 19748604.

It is an arithmetic number, because the mean of its divisors is an integer number (87498684000).

Almost surely, 212113313333000 is an apocalyptic number.

12113313333000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 12113313333000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (22399663104000).

12113313333000 is an abundant number, since it is smaller than the sum of its proper divisors (32686012875000).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12113313333000 is a wasteful number, since it uses less digits than its factorization.

12113313333000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 623294 (or 623280 counting only the distinct ones).

The product of its (nonzero) digits is 1458, while the sum is 24.

Adding to 12113313333000 its reverse (33331331121), we get a palindrome (12146644664121).

The spelling of 12113313333000 in words is "twelve trillion, one hundred thirteen billion, three hundred thirteen million, three hundred thirty-three thousand".