12113330101193 has 2 divisors, whose sum is σ = 12113330101194. Its totient is φ = 12113330101192.

The previous prime is 12113330101183. The next prime is 12113330101237. The reversal of 12113330101193 is 39110103331121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9983122713664 + 2130207387529 = 3159608^2 + 1459523^2 .

It is a cyclic number.

It is not a de Polignac number, because 12113330101193 - 2¹⁰ = 12113330100169 is a prime.

It is a super-2 number, since 2×12113330101193² (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (12113330101183) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6056665050596 + 6056665050597.

It is an arithmetic number, because the mean of its divisors is an integer number (6056665050597).

Almost surely, 2^{12113330101193} is an apocalyptic number.

It is an amenable number.

12113330101193 is a deficient number, since it is larger than the sum of its proper divisors (1).

12113330101193 is an equidigital number, since it uses as much as digits as its factorization.

12113330101193 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1458, while the sum is 29.

The spelling of 12113330101193 in words is "twelve trillion, one hundred thirteen billion, three hundred thirty million, one hundred one thousand, one hundred ninety-three".