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1211340033203 is a prime number
BaseRepresentation
bin10001101000001001011…
…111100000110010110011
311021210200100222111002012
4101220021133200302303
5124321311022030303
62324252032513135
7153342064252226
oct21501137406263
94253610874065
101211340033203
114277a9961963
121769233ab7ab
138a2c8ab8b21
14428b462d5bd
152179a5455d8
hex11a097e0cb3

1211340033203 has 2 divisors, whose sum is σ = 1211340033204. Its totient is φ = 1211340033202.

The previous prime is 1211340033193. The next prime is 1211340033317. The reversal of 1211340033203 is 3023300431121.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1211340033203 is a prime.

It is not a weakly prime, because it can be changed into another prime (1211340033803) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605670016601 + 605670016602.

It is an arithmetic number, because the mean of its divisors is an integer number (605670016602).

Almost surely, 21211340033203 is an apocalyptic number.

1211340033203 is a deficient number, since it is larger than the sum of its proper divisors (1).

1211340033203 is an equidigital number, since it uses as much as digits as its factorization.

1211340033203 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 1211340033203 its reverse (3023300431121), we get a palindrome (4234640464324).

The spelling of 1211340033203 in words is "one trillion, two hundred eleven billion, three hundred forty million, thirty-three thousand, two hundred three".