12113404403 has 2 divisors, whose sum is σ = 12113404404. Its totient is φ = 12113404402.

The previous prime is 12113404357. The next prime is 12113404447. The reversal of 12113404403 is 30440431121.

12113404403 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 12113404403 - 2¹² = 12113400307 is a prime.

It is a Sophie Germain prime.

It is not a weakly prime, because it can be changed into another prime (12113404493) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6056702201 + 6056702202.

It is an arithmetic number, because the mean of its divisors is an integer number (6056702202).

Almost surely, 2^12113404403 is an apocalyptic number.

12113404403 is a deficient number, since it is larger than the sum of its proper divisors (1).

12113404403 is an equidigital number, since it uses as much as digits as its factorization.

12113404403 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 12113404403 its reverse (30440431121), we get a palindrome (42553835524).

The spelling of 12113404403 in words is "twelve billion, one hundred thirteen million, four hundred four thousand, four hundred three".