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121134334341 = 3239168946073
BaseRepresentation
bin111000011010000101…
…0110100000110000101
3102120200001121202200110
41300310022310012011
53441040342144331
6131352013103233
711515551565416
oct1606412640605
9376601552613
10121134334341
11474111a0319
121b587787b19
13b5661c9b17
145c11c6180d
15323e86e946
hex1c342b4185

121134334341 has 8 divisors (see below), whose sum is σ = 162188231040. Its totient is φ = 80418330272.

The previous prime is 121134334337. The next prime is 121134334357. The reversal of 121134334341 is 143433431121.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 121134334341 - 22 = 121134334337 is a prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 121134334299 and 121134334308.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (121134334331) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 84472320 + ... + 84473753.

It is an arithmetic number, because the mean of its divisors is an integer number (20273528880).

Almost surely, 2121134334341 is an apocalyptic number.

It is an amenable number.

121134334341 is a deficient number, since it is larger than the sum of its proper divisors (41053896699).

121134334341 is a wasteful number, since it uses less digits than its factorization.

121134334341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 168946315.

The product of its digits is 10368, while the sum is 30.

Adding to 121134334341 its reverse (143433431121), we get a palindrome (264567765462).

The spelling of 121134334341 in words is "one hundred twenty-one billion, one hundred thirty-four million, three hundred thirty-four thousand, three hundred forty-one".

Divisors: 1 3 239 717 168946073 506838219 40378111447 121134334341