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12113451453 = 34037817151
BaseRepresentation
bin10110100100000010…
…01001100110111101
31011021012121002111010
423102001021212331
5144302020421303
65322001145433
7606116431665
oct132201114675
934235532433
1012113451453
115156800404
12242092b279
1311b0807b6c
1482cb111a5
154ad6d0c03
hex2d20499bd

12113451453 has 4 divisors (see below), whose sum is σ = 16151268608. Its totient is φ = 8075634300.

The previous prime is 12113451451. The next prime is 12113451457. The reversal of 12113451453 is 35415431121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 12113451453 - 21 = 12113451451 is a prime.

It is a super-2 number, since 2×121134514532 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 12113451453.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12113451451) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2018908573 + ... + 2018908578.

It is an arithmetic number, because the mean of its divisors is an integer number (4037817152).

Almost surely, 212113451453 is an apocalyptic number.

It is an amenable number.

12113451453 is a deficient number, since it is larger than the sum of its proper divisors (4037817155).

12113451453 is an equidigital number, since it uses as much as digits as its factorization.

12113451453 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4037817154.

The product of its digits is 7200, while the sum is 30.

Adding to 12113451453 its reverse (35415431121), we get a palindrome (47528882574).

The spelling of 12113451453 in words is "twelve billion, one hundred thirteen million, four hundred fifty-one thousand, four hundred fifty-three".

Divisors: 1 3 4037817151 12113451453