12113515425403 has 8 divisors (see below), whose sum is σ = 13901461687520. Its totient is φ = 10339930177920.

The previous prime is 12113515425373. The next prime is 12113515425433. The reversal of 12113515425403 is 30452451531121.

12113515425403 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is an interprime number because it is at equal distance from previous prime (12113515425373) and next prime (12113515425433).

It is a sphenic number, since it is the product of 3 distinct primes.

It is a de Polignac number, because none of the positive numbers 2^k-12113515425403 is a prime.

It is a super-2 number, since 2×12113515425403² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12113515425433) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3590251848 + ... + 3590255221.

It is an arithmetic number, because the mean of its divisors is an integer number (1737682710940).

Almost surely, 2^{12113515425403} is an apocalyptic number.

12113515425403 is a deficient number, since it is larger than the sum of its proper divisors (1787946262117).

12113515425403 is an equidigital number, since it uses as much as digits as its factorization.

12113515425403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7180507317.

The product of its (nonzero) digits is 72000, while the sum is 37.

Adding to 12113515425403 its reverse (30452451531121), we get a palindrome (42565966956524).

The spelling of 12113515425403 in words is "twelve trillion, one hundred thirteen billion, five hundred fifteen million, four hundred twenty-five thousand, four hundred three".