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12113515425433 is a prime number
BaseRepresentation
bin1011000001000110010111…
…0010001010111010011001
31120220001002201101012021111
42300101211302022322121
53041431434422103213
641432512215340321
72360113130136502
oct260214562127231
946801081335244
1012113515425433
113950349728094
12143781b9816a1
1369b3b82c7286
142dc423a17ba9
15160178970a3d
hexb0465c8ae99

12113515425433 has 2 divisors, whose sum is σ = 12113515425434. Its totient is φ = 12113515425432.

The previous prime is 12113515425373. The next prime is 12113515425437. The reversal of 12113515425433 is 33452451531121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8662826519824 + 3450688905609 = 2943268^2 + 1857603^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12113515425433 is a prime.

It is not a weakly prime, because it can be changed into another prime (12113515425437) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6056757712716 + 6056757712717.

It is an arithmetic number, because the mean of its divisors is an integer number (6056757712717).

Almost surely, 212113515425433 is an apocalyptic number.

It is an amenable number.

12113515425433 is a deficient number, since it is larger than the sum of its proper divisors (1).

12113515425433 is an equidigital number, since it uses as much as digits as its factorization.

12113515425433 is an evil number, because the sum of its binary digits is even.

The product of its digits is 216000, while the sum is 40.

Adding to 12113515425433 its reverse (33452451531121), we get a palindrome (45565966956554).

The spelling of 12113515425433 in words is "twelve trillion, one hundred thirteen billion, five hundred fifteen million, four hundred twenty-five thousand, four hundred thirty-three".