12114013403 has 2 divisors, whose sum is σ = 12114013404. Its totient is φ = 12114013402.

The previous prime is 12114013393. The next prime is 12114013409. The reversal of 12114013403 is 30431041121.

12114013403 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 12114013403 - 2¹² = 12114009307 is a prime.

It is a super-3 number, since 3×12114013403³ (a number of 31 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (12114013409) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6057006701 + 6057006702.

It is an arithmetic number, because the mean of its divisors is an integer number (6057006702).

Almost surely, 2^12114013403 is an apocalyptic number.

12114013403 is a deficient number, since it is larger than the sum of its proper divisors (1).

12114013403 is an equidigital number, since it uses as much as digits as its factorization.

12114013403 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 12114013403 its reverse (30431041121), we get a palindrome (42545054524).

The spelling of 12114013403 in words is "twelve billion, one hundred fourteen million, thirteen thousand, four hundred three".