12114031120143 has 8 divisors (see below), whose sum is σ = 16393116739968. Its totient is φ = 7955483123544.

The previous prime is 12114031120141. The next prime is 12114031120171. The reversal of 12114031120143 is 34102113041121.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 12114031120143 - 2¹ = 12114031120141 is a prime.

It is a super-3 number, since 3×12114031120143³ (a number of 40 digits) contains 333 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12114031120141) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 30134405571 + ... + 30134405972.

It is an arithmetic number, because the mean of its divisors is an integer number (2049139592496).

Almost surely, 2^{12114031120143} is an apocalyptic number.

12114031120143 is a deficient number, since it is larger than the sum of its proper divisors (4279085619825).

12114031120143 is an equidigital number, since it uses as much as digits as its factorization.

12114031120143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 60268811613.

The product of its (nonzero) digits is 576, while the sum is 24.

Adding to 12114031120143 its reverse (34102113041121), we get a palindrome (46216144161264).

The spelling of 12114031120143 in words is "twelve trillion, one hundred fourteen billion, thirty-one million, one hundred twenty thousand, one hundred forty-three".