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121141040003 = 433312795713
BaseRepresentation
bin111000011010010010…
…0011001001110000011
3102120200112020110010022
41300310210121032003
53441044101240003
6131352412524055
711515662564434
oct1606444311603
9376615213108
10121141040003
1147414a60395
121b589a8062b
13b567707079
145c12ac948b
153240246738
hex1c34919383

121141040003 has 4 divisors (see below), whose sum is σ = 121143879048. Its totient is φ = 121138200960.

The previous prime is 121141039991. The next prime is 121141040021. The reversal of 121141040003 is 300040141121.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 121141040003 - 26 = 121141039939 is a prime.

It is a super-3 number, since 3×1211410400033 (a number of 34 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (121141040063) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1354526 + ... + 1441187.

It is an arithmetic number, because the mean of its divisors is an integer number (30285969762).

Almost surely, 2121141040003 is an apocalyptic number.

121141040003 is a deficient number, since it is larger than the sum of its proper divisors (2839045).

121141040003 is an equidigital number, since it uses as much as digits as its factorization.

121141040003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2839044.

The product of its (nonzero) digits is 96, while the sum is 17.

Adding to 121141040003 its reverse (300040141121), we get a palindrome (421181181124).

The spelling of 121141040003 in words is "one hundred twenty-one billion, one hundred forty-one million, forty thousand, three".

Divisors: 1 43331 2795713 121141040003