Search a number
-
+
121141110323 is a prime number
BaseRepresentation
bin111000011010010010…
…0101010011000110011
3102120200112101000120202
41300310210222120303
53441044111012243
6131352414225415
711515663306442
oct1606444523063
9376615330522
10121141110323
1147414aa9202
121b589ab526b
13b56773008c
145c12b06d59
15324025c4b8
hex1c3492a633

121141110323 has 2 divisors, whose sum is σ = 121141110324. Its totient is φ = 121141110322.

The previous prime is 121141110287. The next prime is 121141110329. The reversal of 121141110323 is 323011141121.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 121141110323 - 212 = 121141106227 is a prime.

It is a super-3 number, since 3×1211411103233 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Sophie Germain prime.

It is a junction number, because it is equal to n+sod(n) for n = 121141110295 and 121141110304.

It is not a weakly prime, because it can be changed into another prime (121141110329) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60570555161 + 60570555162.

It is an arithmetic number, because the mean of its divisors is an integer number (60570555162).

Almost surely, 2121141110323 is an apocalyptic number.

121141110323 is a deficient number, since it is larger than the sum of its proper divisors (1).

121141110323 is an equidigital number, since it uses as much as digits as its factorization.

121141110323 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 121141110323 its reverse (323011141121), we get a palindrome (444152251444).

The spelling of 121141110323 in words is "one hundred twenty-one billion, one hundred forty-one million, one hundred ten thousand, three hundred twenty-three".