Base | Representation |
---|---|
bin | 111000011010010010… |
… | …0110001111100010011 |
3 | 102120200112102121000211 |
4 | 1300310210301330103 |
5 | 3441044113010032 |
6 | 131352415024551 |
7 | 11515663465606 |
oct | 1606444617423 |
9 | 376615377024 |
10 | 121141141267 |
11 | 4741501a483 |
12 | 1b589b0b157 |
13 | b5677411a3 |
14 | 5c12b1433d |
15 | 3240266747 |
hex | 1c34931f13 |
121141141267 has 2 divisors, whose sum is σ = 121141141268. Its totient is φ = 121141141266.
The previous prime is 121141141229. The next prime is 121141141273. The reversal of 121141141267 is 762141141121.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 121141141267 - 215 = 121141108499 is a prime.
It is a super-3 number, since 3×1211411412673 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (121141141567) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60570570633 + 60570570634.
It is an arithmetic number, because the mean of its divisors is an integer number (60570570634).
Almost surely, 2121141141267 is an apocalyptic number.
121141141267 is a deficient number, since it is larger than the sum of its proper divisors (1).
121141141267 is an equidigital number, since it uses as much as digits as its factorization.
121141141267 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2688, while the sum is 31.
Adding to 121141141267 its reverse (762141141121), we get a palindrome (883282282388).
The spelling of 121141141267 in words is "one hundred twenty-one billion, one hundred forty-one million, one hundred forty-one thousand, two hundred sixty-seven".
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