Base | Representation |
---|---|
bin | 111000011010010010… |
… | …1100011000001011111 |
3 | 102120200112210210210121 |
4 | 1300310211203001133 |
5 | 3441044140423203 |
6 | 131352423215411 |
7 | 11515665263662 |
oct | 1606445430137 |
9 | 376615723717 |
10 | 121141342303 |
11 | 47415147523 |
12 | 1b589ba7567 |
13 | b5677b1847 |
14 | 5c12b676d9 |
15 | 32402a60bd |
hex | 1c3496305f |
121141342303 has 4 divisors (see below), whose sum is σ = 121186938240. Its totient is φ = 121095746368.
The previous prime is 121141342291. The next prime is 121141342313. The reversal of 121141342303 is 303243141121.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 303243141121 = 3739 ⋅81102739.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-121141342303 is a prime.
It is a super-3 number, since 3×1211413423033 (a number of 34 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (121141342313) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22793983 + ... + 22799296.
It is an arithmetic number, because the mean of its divisors is an integer number (30296734560).
Almost surely, 2121141342303 is an apocalyptic number.
121141342303 is a deficient number, since it is larger than the sum of its proper divisors (45595937).
121141342303 is an equidigital number, since it uses as much as digits as its factorization.
121141342303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 45595936.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 121141342303 its reverse (303243141121), we get a palindrome (424384483424).
The spelling of 121141342303 in words is "one hundred twenty-one billion, one hundred forty-one million, three hundred forty-two thousand, three hundred three".
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