Base | Representation |
---|---|
bin | 10001101000001110010… |
… | …100111000100101101011 |
3 | 11021210220000120210022102 |
4 | 101220032110320211223 |
5 | 124321442302230123 |
6 | 2324304051044015 |
7 | 153344100506243 |
oct | 21501624704553 |
9 | 4253800523272 |
10 | 1211421133163 |
11 | 42784071451a |
12 | 1769465a060b |
13 | 8a30c842a77 |
14 | 428c1300b23 |
15 | 217a2715028 |
hex | 11a0e53896b |
1211421133163 has 2 divisors, whose sum is σ = 1211421133164. Its totient is φ = 1211421133162.
The previous prime is 1211421133121. The next prime is 1211421133177. The reversal of 1211421133163 is 3613311241121.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1211421133163 - 214 = 1211421116779 is a prime.
It is a super-3 number, since 3×12114211331633 (a number of 37 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (1211421133103) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605710566581 + 605710566582.
It is an arithmetic number, because the mean of its divisors is an integer number (605710566582).
Almost surely, 21211421133163 is an apocalyptic number.
1211421133163 is a deficient number, since it is larger than the sum of its proper divisors (1).
1211421133163 is an equidigital number, since it uses as much as digits as its factorization.
1211421133163 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 2592, while the sum is 29.
Adding to 1211421133163 its reverse (3613311241121), we get a palindrome (4824732374284).
The spelling of 1211421133163 in words is "one trillion, two hundred eleven billion, four hundred twenty-one million, one hundred thirty-three thousand, one hundred sixty-three".
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