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121142134221209 is a prime number
BaseRepresentation
bin11011100010110110011001…
…111000001010100110011001
3120212221002000121211000021122
4123202312121320022212121
5111334243042330034314
61105351532253015025
734342142005655603
oct3342663170124631
9525832017730248
10121142134221209
11356660aa665222
12117061a7784475
13527986749778a
1421cb44c33c173
15e012b916528e
hex6e2d99e0a999

121142134221209 has 2 divisors, whose sum is σ = 121142134221210. Its totient is φ = 121142134221208.

The previous prime is 121142134221203. The next prime is 121142134221271. The reversal of 121142134221209 is 902122431241121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 61305721061209 + 59836413160000 = 7829797^2 + 7735400^2 .

It is a cyclic number.

It is not a de Polignac number, because 121142134221209 - 24 = 121142134221193 is a prime.

It is a super-3 number, since 3×1211421342212093 (a number of 43 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (121142134221203) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60571067110604 + 60571067110605.

It is an arithmetic number, because the mean of its divisors is an integer number (60571067110605).

Almost surely, 2121142134221209 is an apocalyptic number.

It is an amenable number.

121142134221209 is a deficient number, since it is larger than the sum of its proper divisors (1).

121142134221209 is an equidigital number, since it uses as much as digits as its factorization.

121142134221209 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 13824, while the sum is 35.

The spelling of 121142134221209 in words is "one hundred twenty-one trillion, one hundred forty-two billion, one hundred thirty-four million, two hundred twenty-one thousand, two hundred nine".