12114214333 has 16 divisors (see below), whose sum is σ = 13621216896. Its totient is φ = 10689940800.

The previous prime is 12114214303. The next prime is 12114214361. The reversal of 12114214333 is 33341241121.

12114214333 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a cyclic number.

It is not a de Polignac number, because 12114214333 - 2¹³ = 12114206141 is a prime.

It is a super-3 number, since 3×12114214333³ (a number of 31 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12114214298 and 12114214307.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12114214303) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 547383 + ... + 569083.

It is an arithmetic number, because the mean of its divisors is an integer number (851326056).

Almost surely, 2^12114214333 is an apocalyptic number.

12114214333 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

12114214333 is a deficient number, since it is larger than the sum of its proper divisors (1507002563).

12114214333 is a wasteful number, since it uses less digits than its factorization.

12114214333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 23604.

The product of its digits is 1728, while the sum is 25.

Adding to 12114214333 its reverse (33341241121), we get a palindrome (45455455454).

The spelling of 12114214333 in words is "twelve billion, one hundred fourteen million, two hundred fourteen thousand, three hundred thirty-three".