Base | Representation |
---|---|
bin | 10110100100001000… |
… | …00110011111011001 |
3 | 1011021021001101202012 |
4 | 23102010012133121 |
5 | 144302220200423 |
6 | 5322025515305 |
7 | 606126133364 |
oct | 132204063731 |
9 | 34237041665 |
10 | 12114225113 |
11 | 51571896a1 |
12 | 2421042b35 |
13 | 11b0a19053 |
14 | 82cc730db |
15 | 4ad7d5078 |
hex | 2d21067d9 |
12114225113 has 2 divisors, whose sum is σ = 12114225114. Its totient is φ = 12114225112.
The previous prime is 12114225083. The next prime is 12114225139. The reversal of 12114225113 is 31152241121.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 6598637824 + 5515587289 = 81232^2 + 74267^2 .
It is an emirp because it is prime and its reverse (31152241121) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12114225113 - 26 = 12114225049 is a prime.
It is a super-3 number, since 3×121142251133 (a number of 31 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (12114225413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6057112556 + 6057112557.
It is an arithmetic number, because the mean of its divisors is an integer number (6057112557).
Almost surely, 212114225113 is an apocalyptic number.
It is an amenable number.
12114225113 is a deficient number, since it is larger than the sum of its proper divisors (1).
12114225113 is an equidigital number, since it uses as much as digits as its factorization.
12114225113 is an evil number, because the sum of its binary digits is even.
The product of its digits is 480, while the sum is 23.
Adding to 12114225113 its reverse (31152241121), we get a palindrome (43266466234).
The spelling of 12114225113 in words is "twelve billion, one hundred fourteen million, two hundred twenty-five thousand, one hundred thirteen".
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