Base | Representation |
---|---|
bin | 10110100100001000… |
… | …11110101010100101 |
3 | 1011021021020102120121 |
4 | 23102010132222211 |
5 | 144302231333013 |
6 | 5322032001541 |
7 | 606130025152 |
oct | 132204365245 |
9 | 34237212517 |
10 | 12114324133 |
11 | 515724702a |
12 | 24210902b1 |
13 | 11b0a52142 |
14 | 82cc9b229 |
15 | 4ad80458d |
hex | 2d211eaa5 |
12114324133 has 8 divisors (see below), whose sum is σ = 12852331520. Its totient is φ = 11386357920.
The previous prime is 12114324127. The next prime is 12114324137. The reversal of 12114324133 is 33142341121.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 12114324133 - 229 = 11577453221 is a prime.
It is a super-3 number, since 3×121143241333 (a number of 31 digits) contains 333 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 12114324098 and 12114324107.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12114324137) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2507808 + ... + 2512633.
It is an arithmetic number, because the mean of its divisors is an integer number (1606541440).
Almost surely, 212114324133 is an apocalyptic number.
It is an amenable number.
12114324133 is a deficient number, since it is larger than the sum of its proper divisors (738007387).
12114324133 is a wasteful number, since it uses less digits than its factorization.
12114324133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5020587.
The product of its digits is 1728, while the sum is 25.
Adding to 12114324133 its reverse (33142341121), we get a palindrome (45256665254).
The spelling of 12114324133 in words is "twelve billion, one hundred fourteen million, three hundred twenty-four thousand, one hundred thirty-three".
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