12114403423 has 4 divisors (see below), whose sum is σ = 12114949680. Its totient is φ = 12113857168.

The previous prime is 12114403391. The next prime is 12114403451. The reversal of 12114403423 is 32430441121.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12114403423 - 2⁵ = 12114403391 is a prime.

It is a super-3 number, since 3×12114403423³ (a number of 31 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12114403463) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 238390 + ... + 284707.

It is an arithmetic number, because the mean of its divisors is an integer number (3028737420).

Almost surely, 2^12114403423 is an apocalyptic number.

12114403423 is a deficient number, since it is larger than the sum of its proper divisors (546257).

12114403423 is an equidigital number, since it uses as much as digits as its factorization.

12114403423 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 546256.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 12114403423 its reverse (32430441121), we get a palindrome (44544844544).

The spelling of 12114403423 in words is "twelve billion, one hundred fourteen million, four hundred three thousand, four hundred twenty-three".