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1211444001217 is a prime number
BaseRepresentation
bin10001101000001111101…
…100000111100111000001
311021210221121121121101101
4101220033230013213001
5124322014131014332
62324310225134401
7153344466052042
oct21501754074701
94253847547341
101211444001217
1142785261363a
1217695218a401
138a3144bb768
14428c43748c9
15217a4730ae7
hex11a0fb079c1

1211444001217 has 2 divisors, whose sum is σ = 1211444001218. Its totient is φ = 1211444001216.

The previous prime is 1211444001197. The next prime is 1211444001223. The reversal of 1211444001217 is 7121004441121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1211443630336 + 370881 = 1100656^2 + 609^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1211444001217 is a prime.

It is a super-3 number, since 3×12114440012173 (a number of 37 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (1211444001227) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605722000608 + 605722000609.

It is an arithmetic number, because the mean of its divisors is an integer number (605722000609).

Almost surely, 21211444001217 is an apocalyptic number.

It is an amenable number.

1211444001217 is a deficient number, since it is larger than the sum of its proper divisors (1).

1211444001217 is an equidigital number, since it uses as much as digits as its factorization.

1211444001217 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1792, while the sum is 28.

Adding to 1211444001217 its reverse (7121004441121), we get a palindrome (8332448442338).

The spelling of 1211444001217 in words is "one trillion, two hundred eleven billion, four hundred forty-four million, one thousand, two hundred seventeen".