Base | Representation |
---|---|
bin | 10110100100001010… |
… | …11010111110100111 |
3 | 1011021021200222110022 |
4 | 23102011122332213 |
5 | 144302312234200 |
6 | 5322041145355 |
7 | 606132104330 |
oct | 132205327647 |
9 | 34237628408 |
10 | 12114571175 |
11 | 51573a56a3 |
12 | 242118b25b |
13 | 11b0b0a715 |
14 | 82cd23287 |
15 | 4ad852885 |
hex | 2d215afa7 |
12114571175 has 12 divisors (see below), whose sum is σ = 17168078256. Its totient is φ = 8307134400.
The previous prime is 12114571141. The next prime is 12114571181. The reversal of 12114571175 is 57117541121.
It is not a de Polignac number, because 12114571175 - 210 = 12114570151 is a prime.
It is a super-3 number, since 3×121145711753 (a number of 31 digits) contains 333 as substring.
It is a Harshad number since it is a multiple of its sum of digits (35).
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 34612886 + ... + 34613235.
It is an arithmetic number, because the mean of its divisors is an integer number (1430673188).
Almost surely, 212114571175 is an apocalyptic number.
12114571175 is a deficient number, since it is larger than the sum of its proper divisors (5053507081).
12114571175 is an equidigital number, since it uses as much as digits as its factorization.
12114571175 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 69226138 (or 69226133 counting only the distinct ones).
The product of its digits is 9800, while the sum is 35.
The spelling of 12114571175 in words is "twelve billion, one hundred fourteen million, five hundred seventy-one thousand, one hundred seventy-five".
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