12115010013 has 4 divisors (see below), whose sum is σ = 16153346688. Its totient is φ = 8076673340.

The previous prime is 12115009987. The next prime is 12115010023. The reversal of 12115010013 is 31001051121.

12115010013 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12115010013 - 2⁸ = 12115009757 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12115009974 and 12115010001.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12115010023) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2019168333 + ... + 2019168338.

It is an arithmetic number, because the mean of its divisors is an integer number (4038336672).

Almost surely, 2^12115010013 is an apocalyptic number.

It is an amenable number.

12115010013 is a deficient number, since it is larger than the sum of its proper divisors (4038336675).

12115010013 is an equidigital number, since it uses as much as digits as its factorization.

12115010013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4038336674.

The product of its (nonzero) digits is 30, while the sum is 15.

Adding to 12115010013 its reverse (31001051121), we get a palindrome (43116061134).

The spelling of 12115010013 in words is "twelve billion, one hundred fifteen million, ten thousand, thirteen".