Base | Representation |
---|---|
bin | 10001101000010100111… |
… | …110010000001011101111 |
3 | 11021211011210101222022120 |
4 | 101220110332100023233 |
5 | 124322204324003012 |
6 | 2324323113044023 |
7 | 153346623351063 |
oct | 21502476201357 |
9 | 4254153358276 |
10 | 1211532641007 |
11 | 427898655a67 |
12 | 1769779b6613 |
13 | 8a329985540 |
14 | 428d2049aa3 |
15 | 217ac3de58c |
hex | 11a14f902ef |
1211532641007 has 32 divisors (see below), whose sum is σ = 1806771111936. Its totient is φ = 717081724800.
The previous prime is 1211532640999. The next prime is 1211532641027. The reversal of 1211532641007 is 7001462351121.
It is not a de Polignac number, because 1211532641007 - 23 = 1211532640999 is a prime.
It is a super-2 number, since 2×12115326410072 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1211532641027) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2876844 + ... + 3270977.
It is an arithmetic number, because the mean of its divisors is an integer number (56461597248).
Almost surely, 21211532641007 is an apocalyptic number.
1211532641007 is a deficient number, since it is larger than the sum of its proper divisors (595238470929).
1211532641007 is a wasteful number, since it uses less digits than its factorization.
1211532641007 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6148031.
The product of its (nonzero) digits is 10080, while the sum is 33.
Adding to 1211532641007 its reverse (7001462351121), we get a palindrome (8212994992128).
The spelling of 1211532641007 in words is "one trillion, two hundred eleven billion, five hundred thirty-two million, six hundred forty-one thousand, seven".
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