Base | Representation |
---|---|
bin | 1011000001001101001100… |
… | …1000101011011011110011 |
3 | 1120220012211120112101120101 |
4 | 2300103103020223123303 |
5 | 3041444214102323410 |
6 | 41433414233453231 |
7 | 2360206445132050 |
oct | 260232310533363 |
9 | 46805746471511 |
10 | 12115350042355 |
11 | 3951100285a1a |
12 | 1438052271217 |
13 | 69b61b417911 |
14 | 2dc559542027 |
15 | 160234a65d3a |
hex | b04d322b6f3 |
12115350042355 has 32 divisors (see below), whose sum is σ = 16629552616320. Its totient is φ = 8300563015680.
The previous prime is 12115350042343. The next prime is 12115350042421. The reversal of 12115350042355 is 55324005351121.
12115350042355 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 12115350042355 - 211 = 12115350040307 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 333361485 + ... + 333397825.
It is an arithmetic number, because the mean of its divisors is an integer number (519673519260).
Almost surely, 212115350042355 is an apocalyptic number.
12115350042355 is a deficient number, since it is larger than the sum of its proper divisors (4514202573965).
12115350042355 is a wasteful number, since it uses less digits than its factorization.
12115350042355 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 44239.
The product of its (nonzero) digits is 90000, while the sum is 37.
Adding to 12115350042355 its reverse (55324005351121), we get a palindrome (67439355393476).
The spelling of 12115350042355 in words is "twelve trillion, one hundred fifteen billion, three hundred fifty million, forty-two thousand, three hundred fifty-five".
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