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12115350042343 is a prime number
BaseRepresentation
bin1011000001001101001100…
…1000101011011011100111
31120220012211120112101112221
42300103103020223123213
53041444214102323333
641433414233453211
72360206445132032
oct260232310533347
946805746471487
1012115350042343
113951100285a09
121438052271207
1369b61b417902
142dc559542019
15160234a65d2d
hexb04d322b6e7

12115350042343 has 2 divisors, whose sum is σ = 12115350042344. Its totient is φ = 12115350042342.

The previous prime is 12115350042293. The next prime is 12115350042421. The reversal of 12115350042343 is 34324005351121.

12115350042343 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 12115350042343 - 221 = 12115347945191 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12115350042299 and 12115350042308.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12115350042743) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6057675021171 + 6057675021172.

It is an arithmetic number, because the mean of its divisors is an integer number (6057675021172).

Almost surely, 212115350042343 is an apocalyptic number.

12115350042343 is a deficient number, since it is larger than the sum of its proper divisors (1).

12115350042343 is an equidigital number, since it uses as much as digits as its factorization.

12115350042343 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 43200, while the sum is 34.

Adding to 12115350042343 its reverse (34324005351121), we get a palindrome (46439355393464).

The spelling of 12115350042343 in words is "twelve trillion, one hundred fifteen billion, three hundred fifty million, forty-two thousand, three hundred forty-three".