Search a number
-
+
12115401441502 = 26057700720751
BaseRepresentation
bin1011000001001101011000…
…1100110000000011011110
31120220012222011020201221111
42300103112030300003132
53041444320232112002
641433423311252234
72360210641044562
oct260232614600336
946805864221844
1012115401441502
1139511272a1957
12143806751a07a
1369b628c72b08
142dc5622c16a2
1516023931a3d7
hexb04d63300de

12115401441502 has 4 divisors (see below), whose sum is σ = 18173102162256. Its totient is φ = 6057700720750.

The previous prime is 12115401441497. The next prime is 12115401441503. The reversal of 12115401441502 is 20514410451121.

It is a semiprime because it is the product of two primes.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12115401441503) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3028850360374 + ... + 3028850360377.

It is an arithmetic number, because the mean of its divisors is an integer number (4543275540564).

Almost surely, 212115401441502 is an apocalyptic number.

12115401441502 is a deficient number, since it is larger than the sum of its proper divisors (6057700720754).

12115401441502 is an equidigital number, since it uses as much as digits as its factorization.

12115401441502 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6057700720753.

The product of its (nonzero) digits is 6400, while the sum is 31.

Adding to 12115401441502 its reverse (20514410451121), we get a palindrome (32629811892623).

The spelling of 12115401441502 in words is "twelve trillion, one hundred fifteen billion, four hundred one million, four hundred forty-one thousand, five hundred two".

Divisors: 1 2 6057700720751 12115401441502