Base | Representation |
---|---|
bin | 1011000001010010010000… |
… | …0000000100101111111001 |
3 | 1120220100100010101211120021 |
4 | 2300110210000010233321 |
5 | 3042010003411204431 |
6 | 41434201020330441 |
7 | 2360255200650304 |
oct | 260244400045771 |
9 | 46810303354507 |
10 | 12116706741241 |
11 | 3951737089973 |
12 | 14383706a3a21 |
13 | 69b7a651511b |
14 | 2dc6477c1b3b |
15 | 1602b3c05b11 |
hex | b0524004bf9 |
12116706741241 has 2 divisors, whose sum is σ = 12116706741242. Its totient is φ = 12116706741240.
The previous prime is 12116706741199. The next prime is 12116706741289. The reversal of 12116706741241 is 14214760761121.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9650249055225 + 2466457686016 = 3106485^2 + 1570496^2 .
It is a cyclic number.
It is not a de Polignac number, because 12116706741241 - 213 = 12116706733049 is a prime.
It is not a weakly prime, because it can be changed into another prime (12116706741541) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6058353370620 + 6058353370621.
It is an arithmetic number, because the mean of its divisors is an integer number (6058353370621).
Almost surely, 212116706741241 is an apocalyptic number.
It is an amenable number.
12116706741241 is a deficient number, since it is larger than the sum of its proper divisors (1).
12116706741241 is an equidigital number, since it uses as much as digits as its factorization.
12116706741241 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 112896, while the sum is 43.
The spelling of 12116706741241 in words is "twelve trillion, one hundred sixteen billion, seven hundred six million, seven hundred forty-one thousand, two hundred forty-one".
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