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12117299353 is a prime number
BaseRepresentation
bin10110100100011111…
…10101000010011001
31011021110211120210221
423102033311002121
5144304012034403
65322215440041
7606164226235
oct132217650231
934243746727
1012117299353
115158999395
122422086021
1311b1554423
1482d4335c5
154adbe0dbd
hex2d23f5099

12117299353 has 2 divisors, whose sum is σ = 12117299354. Its totient is φ = 12117299352.

The previous prime is 12117299339. The next prime is 12117299377. The reversal of 12117299353 is 35399271121.

12117299353 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10624867929 + 1492431424 = 103077^2 + 38632^2 .

It is an emirp because it is prime and its reverse (35399271121) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12117299353 is a prime.

It is a super-2 number, since 2×121172993532 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (12117299333) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6058649676 + 6058649677.

It is an arithmetic number, because the mean of its divisors is an integer number (6058649677).

Almost surely, 212117299353 is an apocalyptic number.

It is an amenable number.

12117299353 is a deficient number, since it is larger than the sum of its proper divisors (1).

12117299353 is an equidigital number, since it uses as much as digits as its factorization.

12117299353 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 102060, while the sum is 43.

The spelling of 12117299353 in words is "twelve billion, one hundred seventeen million, two hundred ninety-nine thousand, three hundred fifty-three".