Base | Representation |
---|---|
bin | 1011000001011110010010… |
… | …0111110111101010000110 |
3 | 1120220122200100100001101222 |
4 | 2300113210213313222012 |
5 | 3042033113212230404 |
6 | 41435453422120342 |
7 | 2360431241411516 |
oct | 260274447675206 |
9 | 46818610301358 |
10 | 12119938398854 |
11 | 3953045295090 |
12 | 1438b12a200b2 |
13 | 69bb9cbb9270 |
14 | 2dc872a8b846 |
15 | 1604027a8dbe |
hex | b05e49f7a86 |
12119938398854 has 16 divisors (see below), whose sum is σ = 21358213122960. Its totient is φ = 5085288838560.
The previous prime is 12119938398851. The next prime is 12119938398859. The reversal of 12119938398854 is 45889383991121.
It is a super-3 number, since 3×121199383988543 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12119938398851) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 21188703209 + ... + 21188703780.
It is an arithmetic number, because the mean of its divisors is an integer number (1334888320185).
Almost surely, 212119938398854 is an apocalyptic number.
12119938398854 is a deficient number, since it is larger than the sum of its proper divisors (9238274724106).
12119938398854 is a wasteful number, since it uses less digits than its factorization.
12119938398854 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 42377407015.
The product of its digits is 134369280, while the sum is 71.
The spelling of 12119938398854 in words is "twelve trillion, one hundred nineteen billion, nine hundred thirty-eight million, three hundred ninety-eight thousand, eight hundred fifty-four".
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