12119993 has 2 divisors, whose sum is σ = 12119994. Its totient is φ = 12119992.

The previous prime is 12119983. The next prime is 12120001. The reversal of 12119993 is 39991121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10936249 + 1183744 = 3307^2 + 1088^2 .

It is an emirp because it is prime and its reverse (39991121) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12119993 - 2¹⁰ = 12118969 is a prime.

It is a Sophie Germain prime.

It is a Chen prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (12119903) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6059996 + 6059997.

It is an arithmetic number, because the mean of its divisors is an integer number (6059997).

Almost surely, 2^12119993 is an apocalyptic number.

It is an amenable number.

12119993 is a deficient number, since it is larger than the sum of its proper divisors (1).

12119993 is an equidigital number, since it uses as much as digits as its factorization.

12119993 is an evil number, because the sum of its binary digits is even.

The product of its digits is 4374, while the sum is 35.

The square root of 12119993 is about 3481.3780317570. The cubic root of 12119993 is about 229.7034173460.

The spelling of 12119993 in words is "twelve million, one hundred nineteen thousand, nine hundred ninety-three".