Base | Representation |
---|---|
bin | 10001101000110000111… |
… | …101001000101000110101 |
3 | 11021212101111210110201020 |
4 | 101220300331020220311 |
5 | 124324140020010010 |
6 | 2324441443251353 |
7 | 153364353645261 |
oct | 21506075105065 |
9 | 4255344713636 |
10 | 1212002110005 |
11 | 428009659a75 |
12 | 176a89079b59 |
13 | 8a3a300aa4b |
14 | 429385350a1 |
15 | 217d8726470 |
hex | 11a30f48a35 |
1212002110005 has 16 divisors (see below), whose sum is σ = 2053274163264. Its totient is φ = 608377529600.
The previous prime is 1212002109979. The next prime is 1212002110013. The reversal of 1212002110005 is 5000112002121.
It is not a de Polignac number, because 1212002110005 - 25 = 1212002109973 is a prime.
It is a super-2 number, since 2×12120021100052 (a number of 25 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2376474471 + ... + 2376474980.
It is an arithmetic number, because the mean of its divisors is an integer number (128329635204).
Almost surely, 21212002110005 is an apocalyptic number.
1212002110005 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
1212002110005 is a deficient number, since it is larger than the sum of its proper divisors (841272053259).
1212002110005 is a wasteful number, since it uses less digits than its factorization.
1212002110005 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4752949476.
The product of its (nonzero) digits is 40, while the sum is 15.
Adding to 1212002110005 its reverse (5000112002121), we get a palindrome (6212114112126).
The spelling of 1212002110005 in words is "one trillion, two hundred twelve billion, two million, one hundred ten thousand, five".
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