Base | Representation |
---|---|
bin | 11011100011101100011111… |
… | …101001101000010000010011 |
3 | 120220010121221020112101111001 |
4 | 123203230133221220100103 |
5 | 111341221014030213212 |
6 | 1105434335333402431 |
7 | 34346266160401201 |
oct | 3343543751502023 |
9 | 526117836471431 |
10 | 121200213132307 |
11 | 356887a36a2801 |
12 | 117154b6199417 |
13 | 5282191c1916a |
14 | 21d019b9d8071 |
15 | e02a67de1657 |
hex | 6e3b1fa68413 |
121200213132307 has 2 divisors, whose sum is σ = 121200213132308. Its totient is φ = 121200213132306.
The previous prime is 121200213132277. The next prime is 121200213132359. The reversal of 121200213132307 is 703231312002121.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 121200213132307 - 223 = 121200204743699 is a prime.
It is not a weakly prime, because it can be changed into another prime (121200213130307) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60600106566153 + 60600106566154.
It is an arithmetic number, because the mean of its divisors is an integer number (60600106566154).
Almost surely, 2121200213132307 is an apocalyptic number.
121200213132307 is a deficient number, since it is larger than the sum of its proper divisors (1).
121200213132307 is an equidigital number, since it uses as much as digits as its factorization.
121200213132307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3024, while the sum is 28.
Adding to 121200213132307 its reverse (703231312002121), we get a palindrome (824431525134428).
The spelling of 121200213132307 in words is "one hundred twenty-one trillion, two hundred billion, two hundred thirteen million, one hundred thirty-two thousand, three hundred seven".
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