Base | Representation |
---|---|
bin | 111000011100000100… |
… | …1100001011000110001 |
3 | 102120211201021001000211 |
4 | 1300320021201120301 |
5 | 3441204440320213 |
6 | 131402400144121 |
7 | 11520322250413 |
oct | 1607011413061 |
9 | 376751231024 |
10 | 121201104433 |
11 | 47445955712 |
12 | 1b5a6008041 |
13 | b576ca7456 |
14 | 5c1aa829b3 |
15 | 324565d53d |
hex | 1c38261631 |
121201104433 has 2 divisors, whose sum is σ = 121201104434. Its totient is φ = 121201104432.
The previous prime is 121201104407. The next prime is 121201104463. The reversal of 121201104433 is 334401102121.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 97155019809 + 24046084624 = 311697^2 + 155068^2 .
It is a cyclic number.
It is not a de Polignac number, because 121201104433 - 29 = 121201103921 is a prime.
It is not a weakly prime, because it can be changed into another prime (121201104403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60600552216 + 60600552217.
It is an arithmetic number, because the mean of its divisors is an integer number (60600552217).
Almost surely, 2121201104433 is an apocalyptic number.
It is an amenable number.
121201104433 is a deficient number, since it is larger than the sum of its proper divisors (1).
121201104433 is an equidigital number, since it uses as much as digits as its factorization.
121201104433 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 576, while the sum is 22.
Adding to 121201104433 its reverse (334401102121), we get a palindrome (455602206554).
The spelling of 121201104433 in words is "one hundred twenty-one billion, two hundred one million, one hundred four thousand, four hundred thirty-three".
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