12120141023 has 4 divisors (see below), whose sum is σ = 12447712440. Its totient is φ = 11792569608.

The previous prime is 12120140999. The next prime is 12120141031. The reversal of 12120141023 is 32014102121.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 32014102121 = 79 ⋅405241799.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12120141023 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12120140992 and 12120141010.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12120141623) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 163785653 + ... + 163785726.

It is an arithmetic number, because the mean of its divisors is an integer number (3111928110).

Almost surely, 2^12120141023 is an apocalyptic number.

12120141023 is a deficient number, since it is larger than the sum of its proper divisors (327571417).

12120141023 is an equidigital number, since it uses as much as digits as its factorization.

12120141023 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 327571416.

The product of its (nonzero) digits is 96, while the sum is 17.

Adding to 12120141023 its reverse (32014102121), we get a palindrome (44134243144).

The spelling of 12120141023 in words is "twelve billion, one hundred twenty million, one hundred forty-one thousand, twenty-three".