Base | Representation |
---|---|
bin | 1110011100101… |
… | …10001100011001 |
3 | 22110001200002222 |
4 | 13032112030121 |
5 | 222011421213 |
6 | 20005433425 |
7 | 3001123643 |
oct | 716261431 |
9 | 273050088 |
10 | 121201433 |
11 | 62462481 |
12 | 3470b875 |
13 | 1c157a32 |
14 | 1214d893 |
15 | a991808 |
hex | 7396319 |
121201433 has 2 divisors, whose sum is σ = 121201434. Its totient is φ = 121201432.
The previous prime is 121201417. The next prime is 121201471. The reversal of 121201433 is 334102121.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 121066009 + 135424 = 11003^2 + 368^2 .
It is an emirp because it is prime and its reverse (334102121) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 121201433 - 24 = 121201417 is a prime.
It is a super-2 number, since 2×1212014332 = 29379574722506978, which contains 22 as substring.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (121201733) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60600716 + 60600717.
It is an arithmetic number, because the mean of its divisors is an integer number (60600717).
Almost surely, 2121201433 is an apocalyptic number.
It is an amenable number.
121201433 is a deficient number, since it is larger than the sum of its proper divisors (1).
121201433 is an equidigital number, since it uses as much as digits as its factorization.
121201433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 17.
The square root of 121201433 is about 11009.1522380245. The cubic root of 121201433 is about 494.8830564133.
Adding to 121201433 its reverse (334102121), we get a palindrome (455303554).
The spelling of 121201433 in words is "one hundred twenty-one million, two hundred one thousand, four hundred thirty-three".
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