Base | Representation |
---|---|
bin | 11011100011101110001111… |
… | …001111000110000111011011 |
3 | 120220010210202201012112202121 |
4 | 123203232033033012013123 |
5 | 111341233332304144143 |
6 | 1105435245211042111 |
7 | 34346363442046153 |
oct | 3343561717060733 |
9 | 526123681175677 |
10 | 121202085224923 |
11 | 3568957441768a |
12 | 11715939140337 |
13 | 52823cca2b381 |
14 | 21d02d84b9763 |
15 | e02b2743a7ed |
hex | 6e3b8f3c61db |
121202085224923 has 2 divisors, whose sum is σ = 121202085224924. Its totient is φ = 121202085224922.
The previous prime is 121202085224833. The next prime is 121202085224933. The reversal of 121202085224923 is 329422580202121.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 121202085224923 - 233 = 121193495290331 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 121202085224923.
It is not a weakly prime, because it can be changed into another prime (121202085224933) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60601042612461 + 60601042612462.
It is an arithmetic number, because the mean of its divisors is an integer number (60601042612462).
Almost surely, 2121202085224923 is an apocalyptic number.
121202085224923 is a deficient number, since it is larger than the sum of its proper divisors (1).
121202085224923 is an equidigital number, since it uses as much as digits as its factorization.
121202085224923 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 276480, while the sum is 43.
The spelling of 121202085224923 in words is "one hundred twenty-one trillion, two hundred two billion, eighty-five million, two hundred twenty-four thousand, nine hundred twenty-three".
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