Search a number
-
+
12120535102993 is a prime number
BaseRepresentation
bin1011000001100000100000…
…1100000111011000010001
31120220201012221010202121021
42300120020030013120101
53042040323441243433
641440032535355441
72360452105332652
oct260301014073021
946821187122537
1012120535102993
1139533210a17a9
12143905a822b81
1369bc666cc935
142dc8cc017529
15160439d7522d
hexb0608307611

12120535102993 has 2 divisors, whose sum is σ = 12120535102994. Its totient is φ = 12120535102992.

The previous prime is 12120535102987. The next prime is 12120535103069. The reversal of 12120535102993 is 39920153502121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9384346038544 + 2736189064449 = 3063388^2 + 1654143^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12120535102993 is a prime.

It is not a weakly prime, because it can be changed into another prime (12120535102493) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6060267551496 + 6060267551497.

It is an arithmetic number, because the mean of its divisors is an integer number (6060267551497).

Almost surely, 212120535102993 is an apocalyptic number.

It is an amenable number.

12120535102993 is a deficient number, since it is larger than the sum of its proper divisors (1).

12120535102993 is an equidigital number, since it uses as much as digits as its factorization.

12120535102993 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 145800, while the sum is 43.

The spelling of 12120535102993 in words is "twelve trillion, one hundred twenty billion, five hundred thirty-five million, one hundred two thousand, nine hundred ninety-three".