Base | Representation |
---|---|
bin | 10001101000110110110… |
… | …010111011111111010011 |
3 | 11021212122100011212210012 |
4 | 101220312302323333103 |
5 | 124324340111200201 |
6 | 2324455303425135 |
7 | 153366653566451 |
oct | 21506662737723 |
9 | 4255570155705 |
10 | 1212100100051 |
11 | 4280599a8385 |
12 | 176ab5a551ab |
13 | 8a3ba3c9719 |
14 | 429475619d1 |
15 | 217e21305bb |
hex | 11a36cbbfd3 |
1212100100051 has 2 divisors, whose sum is σ = 1212100100052. Its totient is φ = 1212100100050.
The previous prime is 1212100100009. The next prime is 1212100100059. The reversal of 1212100100051 is 1500010012121.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1212100100051 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1212100099999 and 1212100100035.
It is not a weakly prime, because it can be changed into another prime (1212100100059) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 606050050025 + 606050050026.
It is an arithmetic number, because the mean of its divisors is an integer number (606050050026).
Almost surely, 21212100100051 is an apocalyptic number.
1212100100051 is a deficient number, since it is larger than the sum of its proper divisors (1).
1212100100051 is an equidigital number, since it uses as much as digits as its factorization.
1212100100051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 20, while the sum is 14.
Adding to 1212100100051 its reverse (1500010012121), we get a palindrome (2712110112172).
The spelling of 1212100100051 in words is "one trillion, two hundred twelve billion, one hundred million, one hundred thousand, fifty-one".
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