Base | Representation |
---|---|
bin | 11011100011110101100111… |
… | …101101110001010010110011 |
3 | 120220011120020011001010122202 |
4 | 123203311213231301102303 |
5 | 111341401101100041201 |
6 | 1105443035535453415 |
7 | 34350064044346232 |
oct | 3343654755612263 |
9 | 526146204033582 |
10 | 121210012112051 |
11 | 35691971998275 |
12 | 1171738b98726b |
13 | 5283094082b25 |
14 | 21d084b190b19 |
15 | e02e3d2e2c6b |
hex | 6e3d67b714b3 |
121210012112051 has 2 divisors, whose sum is σ = 121210012112052. Its totient is φ = 121210012112050.
The previous prime is 121210012112047. The next prime is 121210012112131. The reversal of 121210012112051 is 150211210012121.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 121210012112051 - 22 = 121210012112047 is a prime.
It is not a weakly prime, because it can be changed into another prime (121210012112251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60605006056025 + 60605006056026.
It is an arithmetic number, because the mean of its divisors is an integer number (60605006056026).
Almost surely, 2121210012112051 is an apocalyptic number.
121210012112051 is a deficient number, since it is larger than the sum of its proper divisors (1).
121210012112051 is an equidigital number, since it uses as much as digits as its factorization.
121210012112051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 80, while the sum is 20.
Adding to 121210012112051 its reverse (150211210012121), we get a palindrome (271421222124172).
The spelling of 121210012112051 in words is "one hundred twenty-one trillion, two hundred ten billion, twelve million, one hundred twelve thousand, fifty-one".
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