Base | Representation |
---|---|
bin | 111000011100010101… |
… | …1100000001101110011 |
3 | 102120212100000121122101 |
4 | 1300320223200031303 |
5 | 3441214230400111 |
6 | 131403315121231 |
7 | 11520461051506 |
oct | 1607053401563 |
9 | 376770017571 |
10 | 121210012531 |
11 | 4744a98a483 |
12 | 1b5a8ba3217 |
13 | b578aa600a |
14 | 5c1bd2113d |
15 | 324631cbc1 |
hex | 1c38ae0373 |
121210012531 has 2 divisors, whose sum is σ = 121210012532. Its totient is φ = 121210012530.
The previous prime is 121210012523. The next prime is 121210012541. The reversal of 121210012531 is 135210012121.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 121210012531 - 23 = 121210012523 is a prime.
It is a super-2 number, since 2×1212100125312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 121210012499 and 121210012508.
It is not a weakly prime, because it can be changed into another prime (121210012541) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60605006265 + 60605006266.
It is an arithmetic number, because the mean of its divisors is an integer number (60605006266).
Almost surely, 2121210012531 is an apocalyptic number.
121210012531 is a deficient number, since it is larger than the sum of its proper divisors (1).
121210012531 is an equidigital number, since it uses as much as digits as its factorization.
121210012531 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 120, while the sum is 19.
Adding to 121210012531 its reverse (135210012121), we get a palindrome (256420024652).
The spelling of 121210012531 in words is "one hundred twenty-one billion, two hundred ten million, twelve thousand, five hundred thirty-one".
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