Base | Representation |
---|---|
bin | 1011000001100010010010… |
… | …0000100010101111001001 |
3 | 1120220202110001011012120121 |
4 | 2300120210200202233021 |
5 | 3042042312104014402 |
6 | 41440152031023241 |
7 | 2360466634632451 |
oct | 260304440425711 |
9 | 46822401135517 |
10 | 12121010219977 |
11 | 395354530316a |
12 | 143917196ab21 |
13 | 69c010c81b49 |
14 | 2dc935172d61 |
15 | 160466925837 |
hex | b0624822bc9 |
12121010219977 has 2 divisors, whose sum is σ = 12121010219978. Its totient is φ = 12121010219976.
The previous prime is 12121010219951. The next prime is 12121010220017. The reversal of 12121010219977 is 77991201012121.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 6647754648976 + 5473255571001 = 2578324^2 + 2339499^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12121010219977 is a prime.
It is not a weakly prime, because it can be changed into another prime (12121010219177) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6060505109988 + 6060505109989.
It is an arithmetic number, because the mean of its divisors is an integer number (6060505109989).
Almost surely, 212121010219977 is an apocalyptic number.
It is an amenable number.
12121010219977 is a deficient number, since it is larger than the sum of its proper divisors (1).
12121010219977 is an equidigital number, since it uses as much as digits as its factorization.
12121010219977 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 31752, while the sum is 43.
The spelling of 12121010219977 in words is "twelve trillion, one hundred twenty-one billion, ten million, two hundred nineteen thousand, nine hundred seventy-seven".
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