Base | Representation |
---|---|
bin | 111000011100011000… |
… | …0000101000100010011 |
3 | 102120212102021120002001 |
4 | 1300320300011010103 |
5 | 3441220032241201 |
6 | 131403400534431 |
7 | 11520504205606 |
oct | 1607060050423 |
9 | 376772246061 |
10 | 121211212051 |
11 | 47450629716 |
12 | 1b5a9481417 |
13 | b579105ca7 |
14 | 5c1c15433d |
15 | 32464a8301 |
hex | 1c38c05113 |
121211212051 has 2 divisors, whose sum is σ = 121211212052. Its totient is φ = 121211212050.
The previous prime is 121211211997. The next prime is 121211212081. The reversal of 121211212051 is 150212112121.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 121211212051 - 221 = 121209114899 is a prime.
It is not a weakly prime, because it can be changed into another prime (121211212081) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60605606025 + 60605606026.
It is an arithmetic number, because the mean of its divisors is an integer number (60605606026).
Almost surely, 2121211212051 is an apocalyptic number.
121211212051 is a deficient number, since it is larger than the sum of its proper divisors (1).
121211212051 is an equidigital number, since it uses as much as digits as its factorization.
121211212051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 80, while the sum is 19.
Adding to 121211212051 its reverse (150212112121), we get a palindrome (271423324172).
The spelling of 121211212051 in words is "one hundred twenty-one billion, two hundred eleven million, two hundred twelve thousand, fifty-one".
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