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12121131401 is a prime number
BaseRepresentation
bin10110100100111100…
…11100100110001001
31011021202001021101122
423102132130212021
5144311002201101
65322433525025
7606241626341
oct132236344611
934252037348
1012121131401
115160076475
122423413775
1311b2296702
1482db4dd21
154ae1eb51b
hex2d279c989

12121131401 has 2 divisors, whose sum is σ = 12121131402. Its totient is φ = 12121131400.

The previous prime is 12121131371. The next prime is 12121131457. The reversal of 12121131401 is 10413112121.

12121131401 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11979521401 + 141610000 = 109451^2 + 11900^2 .

It is a cyclic number.

It is not a de Polignac number, because 12121131401 - 222 = 12116937097 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 12121131401.

It is not a weakly prime, because it can be changed into another prime (12121130401) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6060565700 + 6060565701.

It is an arithmetic number, because the mean of its divisors is an integer number (6060565701).

Almost surely, 212121131401 is an apocalyptic number.

It is an amenable number.

12121131401 is a deficient number, since it is larger than the sum of its proper divisors (1).

12121131401 is an equidigital number, since it uses as much as digits as its factorization.

12121131401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 12121131401 its reverse (10413112121), we get a palindrome (22534243522).

The spelling of 12121131401 in words is "twelve billion, one hundred twenty-one million, one hundred thirty-one thousand, four hundred one".