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12121143317953 is a prime number
BaseRepresentation
bin1011000001100010110001…
…1100010001010111000001
31120220202210022121021200021
42300120230130101113001
53042043100142133303
641440213143453441
72360503142145265
oct260305434212701
946822708537607
1012121143317953
11395360345069a
1214391aa457281
1369c032713747
142dc948adc0a5
15160473466ebd
hexb062c7115c1

12121143317953 has 2 divisors, whose sum is σ = 12121143317954. Its totient is φ = 12121143317952.

The previous prime is 12121143317947. The next prime is 12121143318019. The reversal of 12121143317953 is 35971334112121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9516379728769 + 2604763589184 = 3084863^2 + 1613928^2 .

It is a cyclic number.

It is not a de Polignac number, because 12121143317953 - 213 = 12121143309761 is a prime.

It is a super-2 number, since 2×121211433179532 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (12121143317923) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6060571658976 + 6060571658977.

It is an arithmetic number, because the mean of its divisors is an integer number (6060571658977).

Almost surely, 212121143317953 is an apocalyptic number.

It is an amenable number.

12121143317953 is a deficient number, since it is larger than the sum of its proper divisors (1).

12121143317953 is an equidigital number, since it uses as much as digits as its factorization.

12121143317953 is an evil number, because the sum of its binary digits is even.

The product of its digits is 136080, while the sum is 43.

The spelling of 12121143317953 in words is "twelve trillion, one hundred twenty-one billion, one hundred forty-three million, three hundred seventeen thousand, nine hundred fifty-three".