Base | Representation |
---|---|
bin | 1011000001100010111111… |
… | …1111111100001101001110 |
3 | 1120220202221110220110020201 |
4 | 2300120233333330031032 |
5 | 3042043210432001032 |
6 | 41440223115004114 |
7 | 2360504465346655 |
oct | 260305777741516 |
9 | 46822843813221 |
10 | 12121203000142 |
11 | 3953634104815 |
12 | 143920643963a |
13 | 69c041babb52 |
14 | 2dc9529d619c |
15 | 1604788058e7 |
hex | b062fffc34e |
12121203000142 has 4 divisors (see below), whose sum is σ = 18181804500216. Its totient is φ = 6060601500070.
The previous prime is 12121203000091. The next prime is 12121203000149. The reversal of 12121203000142 is 24100030212121.
It is a semiprime because it is the product of two primes.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12121203000149) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3030300750034 + ... + 3030300750037.
It is an arithmetic number, because the mean of its divisors is an integer number (4545451125054).
Almost surely, 212121203000142 is an apocalyptic number.
12121203000142 is a deficient number, since it is larger than the sum of its proper divisors (6060601500074).
12121203000142 is an equidigital number, since it uses as much as digits as its factorization.
12121203000142 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6060601500073.
The product of its (nonzero) digits is 192, while the sum is 19.
Adding to 12121203000142 its reverse (24100030212121), we get a palindrome (36221233212263).
The spelling of 12121203000142 in words is "twelve trillion, one hundred twenty-one billion, two hundred three million, one hundred forty-two", and thus it is an aban number.
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